26p^2-27p+1=0

Solution for 26p^2-27p+1=0 equation:

Simplifying
26p2 + -27p + 1 = 0

Reorder the terms:
1 + -27p + 26p2 = 0

Solving
1 + -27p + 26p2 = 0

Solving for variable 'p'.

Factor a trinomial.
(1 + -26p)(1 + -1p) = 0

Subproblem 1
Set the factor '(1 + -26p)' equal to zero and attempt to solve:

Simplifying
1 + -26p = 0

Solving
1 + -26p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -26p = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -26p = 0 + -1
-26p = 0 + -1

Combine like terms: 0 + -1 = -1
-26p = -1

Divide each side by '-26'.
p = 0.03846153846

Simplifying
p = 0.03846153846
Subproblem 2
Set the factor '(1 + -1p)' equal to zero and attempt to solve:

Simplifying
1 + -1p = 0

Solving
1 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1p = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1p = 0 + -1
-1p = 0 + -1

Combine like terms: 0 + -1 = -1
-1p = -1

Divide each side by '-1'.
p = 1

Simplifying
p = 1
Solution
p = {0.03846153846, 1}